Friday, 11 November 2016

The Time and Work section is very important for IBM placement preparation. Practice and Learn questions on Time and Work topic important for IBM placement aptitude test. 

Question: A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?

Answer: 15 days

Solution:

A+B=1/12
A=1/20
B=1/12-1/20=1/30
A+B/2=1/20+1/(2*30)=1/15

Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same job. How long should it take both A and B, working together but independently to do the same job?

Answer: 40/9

Solution: one day work of A = 1/8
one day work of B = 1/10 
so one day work of A and B together = 1/8 + 1/10 = 9/40
so total days required = 40/9

Question: P can complete a work in 12 days working 8 hours a day,Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?

Answer: 5 + 5/11  hours

Solution: First we have to convert into hours it is easy to solve the question
so p ==> 12 * 8 = 96 h
Q ==> 8 * 10 = 80 h
p+Q= 1/96 + 1/80 = 11/480 
(ie) 480/11 h
per day 8 hours so 480/11*8 = 60/11 days (ie) 5 5/11 days

Question: A can finish a work in 18 days and B can do the same in half the time taken by A. Then, working together , what part of the same work they can finish in a day?

Answer: 1/6

Solution: In one day A can finish work in 1/18 days
similarly B`s work is 1/9 days (since B=half time taken by A)
working together = 1/18+1/9=1/6
So answer is 1/6

Question: A takes twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days, can do the work alone in

Answer: 12 days

Solution: Suppose A, B and C take x, x and x days respectively to finish the work.
2 3
Then, 1 + 2 + 3 = 1
x x x 2
6 = 1
x 2
x = 12.

So, B takes (12/2) = 6 days to finish the work

Question: 10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?

Answer: 225

Solution: 1man 1 day= 1/100
(10man+15woman) 1day = 1/6
10/100+15woman1day = 1/6
15 woman 1day = 1/6 - 1/10
1 woman 1 day = 1/15 (1/6 - 1/10) = 1/225 = 225ans.

Question: Four skilled workers do a job in 5 days, and five semi-skilled workers do the same job in 6 days. How many days will it take for two skilled and one semi-skilled worker to do that job?

Answer: 15/2 days

Solution: 4 skilled in 5 day
2 .......... 10 day

5 semi-skilled in 6 days
1 ............... 30 days

2 skilled & 1 semi skilled in one day = 1/10 + 1/30 =2/15 work
hence, 2/15 work in 1 day
so, 1 work will be 15/2 days Ans

Question: If 20 men or 24 women or 40 boys can do a task in 12 days working for 8 hours a day, how many men working with 6 women and 2 boys take to do a task four times as big working for 5 hours a day for 12 days?

Answer: 122 days

Solution: Amount of work done by 20 men = 24 women = 40 boys or amount of work done by 1 man = 1.2 women = 2 boys.

20*12*8/1=m*12*5/4

m=128

6 women are the equivalent of 6/1.2 = 5 men and 2 boys = 1 man. 
he equivalent of 5 + 1 = 6 men are already working on the project. 
then 128-6=122
Therefore, 122 more men are required to work with 6 women and 2 boys to complete the task. 

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